If P=MC and E = MC^2 how does P = √E ?

If P-MC and E = MC^2 how does P = √E ?
If P=MC and E = MC^2 how does P = √E ?
E-= MC^2 -> √ both sides therefore √E= MC since P=MC -> =√E Hope this helps!
E-= MC^2 -> √ both sides therefore √E= MC since P=MC -> =√E Hope this helps!

Unfortunately, this sounds a bit like a homework question, so I’m going to decline to answer for now. However, I will note that my friend’s proof above is not the correct path. The correct form of the equation is E=M*(C^2), but the helper has assumed (or incorrectly stated), that E=(M*C)^2 in their proof. You cannot root both sides cleanly: √E=(√M)*C.

1. E=MC^2 M=E/C^2 2. P=MC M=C/P 3. E/C^2=C/P E=C^3/P P=C^3/E
1. E=MC^2 M=E/C^2 2. P=MC M=C/P 3. E/C^2=C/P E=C^3/P P=C^3/E

These are all correct. I’m honestly unsure that P can equal √E. But any physics faculty member can probably help answer that definitively.