{"id":9066,"date":"2019-07-15T14:38:25","date_gmt":"2019-07-15T18:38:25","guid":{"rendered":"https:\/\/library.bc.edu\/answerwall\/?p=9066"},"modified":"2019-07-18T09:29:41","modified_gmt":"2019-07-18T13:29:41","slug":"tan10-tan20-tan30-tan80","status":"publish","type":"post","link":"https:\/\/library.bc.edu\/answerwall\/2019\/07\/15\/tan10-tan20-tan30-tan80\/","title":{"rendered":"tan(10\u00b0) + tan(20\u00b0) + tan(30\u00b0) + &#8230; + tan(80\u00b0)=?"},"content":{"rendered":"\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"320\" height=\"311\" src=\"https:\/\/library.bc.edu\/answerwall\/wp-content\/uploads\/2019\/07\/IMG_2988.jpg\" alt=\"tan(10\u00b0) + tan(20\u00b0) + tan(30\u00b0) + ... + tan(80\u00b0)=?\" class=\"wp-image-9065\" srcset=\"https:\/\/library.bc.edu\/answerwall\/wp-content\/uploads\/2019\/07\/IMG_2988.jpg 320w, https:\/\/library.bc.edu\/answerwall\/wp-content\/uploads\/2019\/07\/IMG_2988-300x292.jpg 300w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><figcaption>tan(10\u00b0) + tan(20\u00b0) + tan(30\u00b0) + &#8230; + tan(80\u00b0)=?<\/figcaption><\/figure>\n\n\n\n<p>If you meant what you asked, the answer is 13.2994.  A more interesting question with that sequence would be tan(10\u00b0)* tan(20\u00b0)*tan(30\u00b0)* \u2026 * tan(80\u00b0) = ? Because tan(90\u00b0\u2212x) = cotx = 1\/tanx, tan(10\u00b0)* tan(80\u00b0) = tan(10\u00b0)*1\/tan(10\u00b0) = 1. Similarly, the rest of the sequence cancels out with the final answer being 1. However, as a wall, I&#8217;m more into geometry than trigonometry &#8211; give me more than one right angle, please.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>If you meant what you asked, the answer is 13.2994. A more interesting question with that sequence would be tan(10\u00b0)* tan(20\u00b0)*tan(30\u00b0)* \u2026 * tan(80\u00b0) = ? Because tan(90\u00b0\u2212x) = cotx = 1\/tanx, tan(10\u00b0)* tan(80\u00b0) = tan(10\u00b0)*1\/tan(10\u00b0) = 1. Similarly, the rest of the sequence cancels out with the final answer being 1. However, as a &hellip; <\/p>\n<p class=\"link-more\"><a href=\"https:\/\/library.bc.edu\/answerwall\/2019\/07\/15\/tan10-tan20-tan30-tan80\/\" class=\"more-link\">Continue reading<span class=\"screen-reader-text\"> &#8220;tan(10\u00b0) + tan(20\u00b0) + tan(30\u00b0) + &#8230; + tan(80\u00b0)=?&#8221;<\/span><\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[99],"class_list":["post-9066","post","type-post","status-publish","format-standard","hentry","category-academics","tag-mathematics"],"_links":{"self":[{"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/posts\/9066","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/comments?post=9066"}],"version-history":[{"count":3,"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/posts\/9066\/revisions"}],"predecessor-version":[{"id":9101,"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/posts\/9066\/revisions\/9101"}],"wp:attachment":[{"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/media?parent=9066"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/categories?post=9066"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/library.bc.edu\/answerwall\/wp-json\/wp\/v2\/tags?post=9066"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}